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WAEC Mathematics 2010 past questions

Ten questions from the 2010 WAEC Mathematics paper, with answers and explanations. We hold 29 questions from this paper, and the Skolra app has all of them.

WAEC Mathematics 2010 questions and answers

  1. 1.A car uses one litre of petrol for every 14km. If one of petrol cost N63.00, how far can the car go with N900.00 worth of petrol?
    1. A
      250 km
    2. B
      200 km
      Correct
    3. C
      100 km
    4. D
      150 km
    Show answerHide answer

    Answer: B

    Step 1: Find the number of litres purchasable.
    Litres = 90063=1007\frac{900}{63} = \frac{100}{7}

    Step 2: Calculate the distance.
    Distance = 1007×14=100×147=200\frac{100}{7} \times 14 = \frac{100 \times 14}{7} = 200 km

  2. 2.The mean of the numbers 2, 5, 2x and 7 is less than or equal to 5. Find the range of the values of x
    1. A
      x ≤ 4
    2. B
      x ≤ 2
    3. C
      x ≤ 3
      Correct
    4. D
      x ≥ 3
    Show answerHide answer

    Answer: C

    The mean of 2, 5, 2x and 7 is:

    2+5+2x+74≤5\frac{2 + 5 + 2x + 7}{4} \leq 5

    14+2x4≤5\frac{14 + 2x}{4} \leq 5

    14+2x≤2014 + 2x \leq 20

    2x≤62x \leq 6

    x≤3x \leq 3

  3. 3.A rectangle has length xcm and width (x - 1)cm. If the perimeter is 16cm. Find the value of x
    1. A
      5.0
    2. B
      6.0
    3. C
      4.5
      Correct
    4. D
      3.5
    Show answerHide answer

    Answer: C

    Step 1: Write the perimeter formula.
    Perimeter = 2(length + width) = 2(x + x − 1) = 2(2x − 1)

    Step 2: Set equal to 16 and solve.
    2(2x − 1) = 16
    4x − 2 = 16
    4x = 18
    x = 4.5

  4. 4.The sum of 6 and one-third of x is one more than twice x, find x
    1. A
      2
    2. B
      5
    3. C
      3
      Correct
    4. D
      4
    Show answerHide answer

    Answer: C

    Step 1: Translate into an equation.
    6+x3=1+2x6 + \frac{x}{3} = 1 + 2x

    Step 2: Solve.
    6−1=2x−x36 - 1 = 2x - \frac{x}{3}
    5=6x−x3=5x35 = \frac{6x - x}{3} = \frac{5x}{3}
    15=5x15 = 5x
    x=3x = 3

  5. 5.Given that 5n+3252n−2\frac{5^{n +3}}{25^{2n -2}} = 5o, find n
    1. A
      2
    2. B
      73\frac{7}{3}
      Correct
    3. C
      1
    4. D
      37\frac{3}{7}
    Show answerHide answer

    Answer: B

    Step 1: Express 25 as a power of 5.
    252n−2=(52)2n−2=54n−425^{2n-2} = (5^2)^{2n-2} = 5^{4n-4}

    Step 2: Simplify the left side.
    5n+354n−4=5(n+3)−(4n−4)=5−3n+7\frac{5^{n+3}}{5^{4n-4}} = 5^{(n+3)-(4n-4)} = 5^{-3n+7}

    Step 3: Set equal to 50 and solve.
    −3n+7=0-3n + 7 = 0
    n=73n = \frac{7}{3}

  6. 6.What is the length of a rectangular garden whose perimeter is 32cm and area 39cm2?
    1. A
      9 cm
    2. B
      13 cm
      Correct
    3. C
      3 cm
    4. D
      16 cm
    Show answerHide answer

    Answer: B

    Let length = l and width = w.

    Perimeter: 2(l + w) = 32 → l + w = 16 → w = 16 − l

    Area: lw = 39

    Substituting: l(16 − l) = 39

    l2−16l+39=0l^2 - 16l + 39 = 0

    (l−3)(l−13)=0(l - 3)(l - 13) = 0

    l = 3 or l = 13

    The length (longer side) = 13 cm (width = 3 cm).

  7. 7.Factorize: x + y - ax = ay
    1. A
      (1 - a)(x + y)
      Correct
    2. B
      (a - 1)(x + y)
    3. C
      (1 - a)(x - y)
    4. D
      (1 + a)(x - y)
    Show answerHide answer

    Answer: A

    Step 1: Bring all terms to one side.
    x + y − ax − ay = 0

    Step 2: Group and factorise.
    x(1 − a) + y(1 − a) = 0
    (1 − a)(x + y) = 0

  8. 8.

    No. of pets01234No. of students845103\begin{array}{c|c} \text{No. of pets} & 0 & 1 & 2 & 3 & 4 \\ \hline \text{No. of students} & 8 & 4 & 5 & 10 & 3\end{array}

    The table shows the number of pets kept by 30 students in a class. If a student is picked at random from the class. What is the probability that he/she kept more than one pet?

    1. A
      12\frac{1}{2}
    2. B
      25\frac{2}{5}
    3. C
      13\frac{1}{3}
    4. D
      35\frac{3}{5}
      Correct
    Show answerHide answer

    Answer: D

    Step 1: Count students with more than 1 pet (i.e. 2, 3 or 4 pets).
    5 + 10 + 3 = 18 students

    Step 2: Calculate the probability.
    P = 1830=35\frac{18}{30} = \frac{3}{5}

  9. 9.The sum of 2 consecutive whole numbers is 56\frac{5}{6} of their product, find the numbers
    1. A
      4 and 5
    2. B
      3 and 4
    3. C
      2 and 3
      Correct
    4. D
      1 and 2
    Show answerHide answer

    Answer: C

    Step 1: Set up the equation.
    Let the numbers be n and n + 1.
    n+(n+1)=56⋅n(n+1)n + (n+1) = \frac{5}{6} \cdot n(n+1)
    2n+1=56n(n+1)2n + 1 = \frac{5}{6}n(n+1)

    Step 2: Multiply through by 6.
    12n+6=5n(n+1)=5n2+5n12n + 6 = 5n(n+1) = 5n^2 + 5n
    5n2−7n−6=05n^2 - 7n - 6 = 0

    Step 3: Solve the quadratic.
    (5n+3)(n−2)=0(5n + 3)(n - 2) = 0
    n = 2 (taking the positive whole-number root)

    Step 4: State the answer.
    The numbers are 2 and 3. Check: 2 + 3 = 5 and 56×2×3=5\frac{5}{6}\times 2\times 3 = 5. ✓

  10. 10.The sum of the exterior of an n-sided convex polygon is half the sum of its interior angle. find n
    1. A
      6
      Correct
    2. B
      8
    3. C
      12
    4. D
      4
    Show answerHide answer

    Answer: A

    For any convex polygon:

    Sum of exterior angles = 360°

    Sum of interior angles = (n − 2) × 180°

    Setting exterior = ½ × interior:

    360=12(n−2)×180360 = \frac{1}{2}(n-2) \times 180

    360=90(n−2)360 = 90(n-2)

    4=n−24 = n - 2

    n=6n = 6

The questions come from past JAMB, WAEC and NECO papers. We use software to help write the answer options and explanations, and every answer is checked twice before it goes on the site. How we check

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