WAEC Physics 2012 past questions
Ten questions from the 2012 WAEC Physics paper, with answers and explanations. We hold 50 questions from this paper, and the Skolra app has all of them.
WAEC Physics 2012 questions and answers
-
1.When two waves are superimposed on each other, the following occurrences are possible, except
- ArefractionCorrect
- Bdestructive interference
- Cconstructive interference
- Dbeats
Show answerHide answer
Answer: A
Refraction is not a result of superposition; it occurs when a wave passes from one medium to another of different optical density, changing its speed and direction. Constructive interference, destructive interference, and beats are all direct consequences of the superposition principle.
- A
-
2.A girl stands on a scale in a lift. If the reading on the scale is less than her weight, then the lift is moving
- Aupward with uniform acceleration
- Bupward at constant velocity
- Cdownward at constant velocity
- Ddownward with uniform accelerationCorrect
Show answerHide answer
Answer: D
When a lift accelerates downward, the normal reaction N on the girl is reduced. By Newton's 2nd law:
N = m(g − a)
Since (g − a) < g, the scale reading N is less than the true weight mg. At constant velocity (up or down), a = 0 and N = mg, so the reading equals her weight.
- A
-
3.A block of wood of density 0.6 gcm-3, weighing 3.06N in air, floats freely in a liquid of density 0.9 gcm-3. Calculate volume of the portion immersed (g = 10ms-2)
- A510 cm³
- B340 cm³Correct
- C170 cm³
- D255 cm³
Show answerHide answer
Answer: B
Mass of wood = W/g = 3.06/10 = 0.306 kg = 306 g
Volume of wood = mass/density = 306/0.6 = 510 cm³
For a floating body: weight = weight of liquid displaced
Fraction immersed = ρwood/ρliquid = 0.6/0.9 = 2/3
Vimmersed = (2/3) × 510 = 340 cm³
- A
-
4.The sound heard by a person after the reflection of the sound generated by him is called
- Adiffraction
- BechoCorrect
- Creverberation
- Dresonance
Show answerHide answer
Answer: B
An echo is the distinct repetition of a sound heard by a person after it has been reflected from a surface (such as a cliff or wall). For an echo to be heard distinctly, the reflecting surface must be at least about 17 m away so the reflected sound arrives more than 0.1 s after the original.
- A
-
5.The time of flight for a projectile motion is given by the expression
- AT = 2u sin θ / gCorrect
- BT = u sin θ / g
- CT = 2u cos θ / g
- DT = u cos θ / g
Show answerHide answer
Answer: A
For a projectile launched at initial speed u and angle θ to the horizontal, the vertical component is u sin θ.
Time to reach maximum height: t = u sin θ / g
Total time of flight: T = 2u sin θ / g (the factor 2 accounts for the symmetric return journey).
- A
-
6.Which of the following properties of waves is exclusive to transverse waves?
- ApolarizationCorrect
- Bdiffraction
- Crefraction
- Dreflection
Show answerHide answer
Answer: A
Polarization is the property exclusive to transverse waves. It restricts the oscillation of the wave to a single plane perpendicular to the direction of propagation. Longitudinal waves (e.g. sound) cannot be polarized because their oscillations are parallel to the direction of travel. Reflection, diffraction, and refraction occur for both transverse and longitudinal waves.
- A
-
7.Which of the following arrangements of radiations is in the order of decreasing penetrating power?
- Aβ, α, γ
- Bγ, β, αCorrect
- Cα, γ, β
- Dα, β, γ
Show answerHide answer
Answer: B
In decreasing order of penetrating power:
γ (gamma) → β (beta) → α (alpha)- Gamma rays: electromagnetic radiation; can penetrate several centimetres of lead or metres of concrete.
- Beta particles: stopped by a few millimetres of aluminium.
- Alpha particles: stopped by a sheet of paper or a few centimetres of air.
- A
-
8.a bird flies at 10ms-1 for 3s, 15ms-1 for 3s and 20 ms-1 for 4s. Calculate the bird's average speed
- A16.5 ms⁻¹
- B15.0 ms⁻¹
- C14.5 ms⁻¹
- D15.5 ms⁻¹Correct
Show answerHide answer
Answer: D
Average speed = Total distance ÷ Total time
Total distance = (10 × 3) + (15 × 3) + (20 × 4) = 30 + 45 + 80 = 155 m
Total time = 3 + 3 + 4 = 10 s
Average speed = 155 ÷ 10 = 15.5 ms⁻¹
- A
-
9.Six dry cells each of e.m.f. 2.0 and internal resistance of 1.0 are connected in parallel across a load of 3.0. Calculate the effective current in the circuit
- A4.00 A
- B1.05 A
- C0.63 ACorrect
- D2.00 A
Show answerHide answer
Answer: C
For identical cells in parallel: equivalent EMF = 2.0 V; equivalent internal resistance = r/n = 1.0/6 Ω
Total resistance = Rload + reff = 3.0 + 1/6 = 19/6 Ω
I = EMF / Rtotal = 2.0 / (19/6) = 12/19 ≈ 0.63 A
- A
-
10.An atom in an excited state is one whose
- Aelectrons have moved to higher energy levels by absorbing energyCorrect
- Bnucleus has gained extra neutrons from the environment
- Celectrons have permanently escaped from the atom
- Dnucleus has lost some protons to become more stable
Show answerHide answer
Answer: A
An atom is in an excited state when one or more of its electrons have absorbed energy and jumped from a lower energy level to a higher energy level (a level further from the nucleus). The atom is unstable in this state and will return to the ground state by emitting the absorbed energy as a photon of electromagnetic radiation (e.g., visible light, UV or X-rays), a process known as emission.
- A
The questions come from past JAMB, WAEC and NECO papers. We use software to help write the answer options and explanations, and every answer is checked twice before it goes on the site. How we check
Spotted a wrong answer? Tell us from the app or on the contact page and we check it.
Practise all 50 questions we hold from the 2012 paper, on a timed CBT screen
Every question has the answer and an explanation, in the Skolra app.